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Algebra 2 Unit 4: Review
You may not use a calculator.
1.  Select all expressions that are equivalent to \(4^{3/2}\).
2.  How many real solutions does \(x^2 + 2x + 5 = 0\) have?
3.  Select all the solutions, real or complex, to \((x - 1)^2 = -4\).
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4.  Let \(p = 3 + 2i\) and \(q = 1 - 5i\).  Write each expression in the form \(a + bi\).
a.  \(p + q\)
b.  \(p - q\)
c.  \(pq\)
5a.  Show how to solve the equation \(\sqrt{(2x + 3)} - 5 = -2\).
b.  Explain why \(\sqrt{(2x + 3)} + 5 = -2\) has no real solution.
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6a.  Here is a graph of \(g(x) = \sqrt[3]{(x)}\).
-10 -8 -6 -4 -2 2 4 6 8 10 x -3 -2 -1 1 2 3 y
Use the graph to explain why there is only one real solution to every equation of the form \(\sqrt[3]{(x)} = a\) in which \(a\) is a real number.
b.  Use the meaning of cube roots to show how to find an exact solution to the equation \(\sqrt[3]{(x + 1)} = 2\) without using a graph.
c.  Use the meaning of cube roots to show how to find an exact solution to the equation \(\sqrt[3]{(x)} - 1 = 2\) without using a graph.
7.  Noah and Lin are each trying to solve the equation \(x^2 - 4x + 5 = 0\). They know that the solutions to \(x^2 = -1\) are \(i\) and \(-i\) but are not sure how to use this to solve their equation.
a.  Here is Noah's work:
\(x^2 - 4x + 5 = 0\)
\(x^2 - 4x = -5\)
\(x^2 - 4x + 4 = -5 + 4\)
\((x - 2)^2 = -1\)
Show how Noah can finish his work using complex numbers.
b.  Lin decides to use the quadratic formula. Here is her work:
\(\displaystyle x = \frac{-b \pm \sqrt{(b^2 - 4ac)}}{2a}\)
\(\displaystyle x = \frac{-(-4) \pm \sqrt{((-4)^2 - 4(1)(5))}}{2(1)}\)
\(\displaystyle x = \frac{4 \pm \sqrt{(16 - 20)}}{2}\)
Lin knows \(16 - 20\) is a negative number and isn't sure what to do next. Show how Lin can write her solution using \(i\).
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Unit 4 Reference Sheet
Key terms, definitions, and rules. Use this page during the review.
TermDefinitionRules / Outcomes
Rational Exponent
\(b^{m/n}\)
A fractional exponent. The denominator is the index of the root; the numerator is the power applied to the base.
\(b^{m/n} = \left(\sqrt[n]{(b)}\right)^m = \sqrt[n]{(b^m)}\)
Order: root and power can be applied in either order.
Discriminant
\(b^2 - 4ac\)
The expression under the radical in the quadratic formula. Determines the number and type of solutions to \(ax^2+bx+c=0\).
If \(b^2-4ac > 0\): 2 real solutions
If \(b^2-4ac = 0\): 1 real solution
If \(b^2-4ac < 0\): 0 real solutions (2 complex)
Imaginary Unit
\(i\)
Defined so that \(i^2 = -1\). It is the square root of \(-1\). It is not a real number.
\(\sqrt{(-a)} = \sqrt{(a)} \cdot i\)   for \(a > 0\)
Replace every \(i^2\) in a product with \(-1\).
Complex Number
\(a + bi\)
Standard form with real part \(a\) and imaginary part \(bi\), where \(a\) and \(b\) are real numbers.
Add/Subtract: combine real parts, then imaginary parts
Multiply: FOIL, then replace \(i^2\) with \(-1\)
Square Root Equation
\(\sqrt{(f(x))} = k\)
An equation with a variable inside a square root. Isolate the radical, then square both sides.
If \(k \geq 0\): possible solution — check for extraneous
If \(k < 0\): no real solution (\(\sqrt{\phantom{x}}\) is never negative)
Cube Root Equation
\(\sqrt[3]{(f(x))} = k\)
An equation with a variable inside a cube root. Isolate the radical, then cube both sides.
Always exactly 1 real solution for any value of \(k\)
No extraneous solutions.
Completing the Square
\((x+p)^2 = q\)
Rewriting a quadratic so one side is a perfect square trinomial. Then take square roots of both sides.
If \(q > 0\): 2 real solutions \(x = -p \pm \sqrt{(q)}\)
If \(q = 0\): 1 real solution \(x = -p\)
If \(q < 0\): 2 complex solutions \(x = -p \pm i\sqrt{(-q)}\)
Quadratic Formula
\(\dfrac{-b \pm \sqrt{(b^2-4ac)}}{2a}\)
Gives all solutions to \(ax^2+bx+c=0\) directly from its coefficients. Works for every quadratic.
Sign of \(b^2-4ac\) determines solution type (see Discriminant row)
When \(b^2-4ac < 0\): \(\sqrt{(b^2-4ac)} = i\sqrt{(|b^2-4ac|)}\)